练习一

实现代码：

def merge(list1, list2):
    merged_list = []
    i = 0
    j = 0

    while i < len(list1) and j < len(list2):
        if list1[i] < list2[j]:
            merged_list.append(list1[i])
            i += 1
        else:
            merged_list.append(list2[j])
            j += 1

    merged_list += list1[i:]
    merged_list += list2[j:]

    return merged_list


list1 = input("Enter list1: ").split()
list1 = [int(x) for x in list1]

list2 = input("Enter list2: ").split()
list2 = [int(x) for x in list2]

merged = merge(list1, list2)
print("The merged list is", ' '.join(map(str, merged)))

结果截图：

练习二

实现代码：

def isConsecutiveFour(values):
    for i in range(len(values) - 3):
        if values[i] == values[i + 1] == values[i + 2] == values[i + 3]:
            return True
    return False


input_values = input("输入空格分开的整数序列: ").split()
values = [int(x) for x in input_values]

if isConsecutiveFour(values):
    print("包含具有相同值的四个连续数字")
else:
    print("不包含具有相同值的四个连续数字")

练习三

实现代码：

def countnum():
    input_numbers = input("Enter integers between 1 and 100: ").split()
    counts = {}

    for number in input_numbers:
        number = int(number)
        if 1 <= number <= 100:
            if number in counts:
                counts[number] += 1
            else:
                counts[number] = 1

    for number, count in sorted(counts.items()):
        if count == 1:
            print(f"{number} occurs 1 time")
        else:
            print(f"{number} occurs {count} times")


countnum()

结果截图：