net8 golang python性能比较

net8正式版出来两个月，现在性能到底如何呢，做个简单的例子和其他语言比较一下，测试内容是查找1000000以内的质数，代码不多，但包含了循环计算和Math库函数调用，直观的看一下语言之间差距是多少，心里有个底，测试机是笔记本surface book 2 intel i7 有个四五年了，不过还能跑

首先来看看google的王牌语言golang，语法简单但性能号称不输C++，先看一下go 1.20.2

package main

import (
	"fmt"
	"math"
	"time"
)

func isPrime(num int) bool {
	if num <= 1 {
		return false
	}
	for i := 2; i <= int(math.Sqrt(float64(num))); i++ {
		if num%i == 0 {
			return false
		}
	}
	return true
}

func countPrimes(n int) int {
	count := 0
	for i := 2; i < n; i++ {
		if isPrime(i) {
			count++
		}
	}
	return count
}

func main() {
	num := 1000000

	startTime := time.Now()
	result := countPrimes(num)
	endTime := time.Now()

	fmt.Printf("The number of prime numbers less than %d is: %d\n", num, result)
	fmt.Printf("Execution time: %v\n", endTime.Sub(startTime))
}

编译之后看看耗时是多少

然后看看net6

using System;
using System.Diagnostics;

namespace FindPrimeNet6
{
    class Program
    {
        static bool IsPrime(int num)
        {
            if (num <= 1)
            {
                return false;
            }
            for (int i = 2; i <= Math.Sqrt(num); i++)
            {
                if (num % i == 0)
                {
                    return false;
                }
            }
            return true;
        }

        static int CountPrimes(int n)
        {
            int count = 0;
            for (int i = 2; i < n; i++)
            {
                if (IsPrime(i))
                {
                    count++;
                }
            }
            return count;
        }

        static void Main(string[] args)
        {
            int num = 1000000;

            Stopwatch timer = Stopwatch.StartNew();

            int result = CountPrimes(num);

            timer.Stop();

            Console.WriteLine($"The number of prime numbers less than {num} is: {result}");
            Console.WriteLine($"Execution time: {timer.ElapsedMilliseconds:F4} ms");
        }
    }
}

运行一下看看

然后重头来了net8 开启aot怎么样呢

看来速度没提升，应该是启动速度提高了

然后我们再看看大家心目中最慢的python，装了3.11.7版本

#import numba
import math
import time

#@numba.jit
def is_prime(num):
    if num <= 1:
        return False
    for i in range(2, int(math.sqrt(num)) + 1):
        if num % i == 0:
            return False
    return True
    
#@numba.jit
def count_primes(n):
    count = 0
    for i in range(2, n):
        if is_prime(i):
            count += 1
    return count

num = 1000000
start_time = time.perf_counter()
result = count_primes(num)
end_time = time.perf_counter()

time_elapsed = end_time - start_time

print(f"The number of prime numbers less than {num} is: {result}")
print(f"Execution time: {time_elapsed*1000:.4f}ms")

看看普通模式跑跑要多少毫秒