百马百担c语言编程

以下是一个百马百担问题的C语言编程实现：

这个程序首先读取三个整数n、m、k，分别表示马的数量、担的数量和人的数量。然后分别读取n个马的数量、m个担的重量、k个人的人数，存储在数组a、b、c中。接着计算马的总重量sum_a、担的总重量sum_b、人的总重量sum_c，如果三者相等则输出"YES"，否则输出"NO"。

当然，这个程序可以根据需要进行一些改进。以下是一个可能的改进版本，它可以处理更一般的情况，并且输出更详细的信息：

#include <stdio.h>
int main() {
int n, m, k;
scanf("%d%d%d", &n, &m, &k);
int a[n], b[m], c[k];
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
for (int i = 0; i < m; i++) {
scanf("%d", &b[i]);
}
for (int i = 0; i < k; i++) {
scanf("%d", &c[i]);
}
int sum_a = 0, sum_b = 0, sum_c = 0;
for (int i = 0; i < n; i++) {
sum_a += a[i];
}
for (int i = 0; i < m; i++) {
sum_b += b[i];
}
for (int i = 0; i < k; i++) {
sum_c += c[i];
}
if (sum_a == sum_b && sum_b == sum_c) {
printf("YES, all weights are equal.\n");
} else {
printf("NO, weights are not equal.\n");
if (sum_a != sum_b) {
printf("The total weight of horses is %d, but the total weight of donkeys is %d.\n", sum_a, sum_b);
}
if (sum_b != sum_c) {
printf("The total weight of donkeys is %d, but the total weight of people is %d.\n", sum_b, sum_c);
}
}
return 0;
}

这个版本的程序在比较重量之前先分别计算了马、担和人各自的重量总和，这样如果重量不等，程序可以输出哪个总和与其它总和不相等，以便用户更好地理解问题。

好的，以下是对上述程序的进一步改进，增加了对输入数据的验证和错误处理：

#include <stdio.h>
int main() {
int n, m, k;
scanf("%d%d%d", &n, &m, &k);
// 检查输入数据的有效性
if (n <= 0 || m <= 0 || k <= 0) {
printf("Invalid input: all counts must be positive.\n");
return 0;
}
int a[n], b[m], c[k];
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
for (int i = 0; i < m; i++) {
scanf("%d", &b[i]);
}
for (int i = 0; i < k; i++) {
scanf("%d", &c[i]);
}
// 检查输入数据的总和是否为整数，并且不超过整数的最大值
long long sum_a = 0, sum_b = 0, sum_c = 0;
for (int i = 0; i < n; i++) {
sum_a += a[i];
}
for (int i = 0; i < m; i++) {
sum_b += b[i];
}
for (int i = 0; i < k; i++) {
sum_c += c[i];
}
if (sum_a != sum_b || sum_b != sum_c) {
printf("The total weights are not equal.\n");
if (sum_a != sum_b) {
printf("The total weight of horses is %lld, but the total weight of donkeys is %lld.\n", sum_a, sum_b);
}
if (sum_b != sum_c) {
printf("The total weight of donkeys is %lld, but the total weight of people is %lld.\n", sum_b, sum_c);
}
} else {
printf("YES, all weights are equal.\n");
}
return 0;
}